Import Question JSON

Current Question (ID: 7929)

Question:
$\text{The correct order of increasing electron affinity for the elements, O, S, F and Cl is:}$
Options:
  • 1. $\text{Cl} < \text{F} < \text{O} < \text{S}$
  • 2. $\text{O} < \text{S} < \text{F} < \text{Cl}$ (Correct)
  • 3. $\text{F} < \text{S} < \text{O} < \text{Cl}$
  • 4. $\text{S} < \text{O} < \text{Cl} < \text{F}$
Solution:
$\text{HINT: 3rd-period elements are having higher electron affinity than 2nd period elements.}$ $\text{Explanation:}$ $\text{The electron gain enthalpy is seen to decrease on moving down a group and increases from moving left to right in a period. Due to the smaller size of the members of III period compared to the corresponding members of second period, they have higher electron gain enthalpy.}$ $\text{Thus, the electron gain enthalpy of Cl and F (17 group) is higher as compared to O and S (16 group).}$ $\text{Cl has higher electron gain enthalpy as compared to F, this is because due to the small size of F atom, the incoming electron experiences a greater force of repulsion.}$ $\text{Similarly, the electron gain enthalpy of S is higher as compared to O due to its small size.}$ $\text{Therefore, the correct order of electron gain enthalpy of given elements is :}$ $\text{O} < \text{S} < \text{F} < \text{Cl}$ $\text{Note: Electron affinity and electron gain enthalpy are related concepts:}$ $\text{- Electron affinity is the magnitude of energy released when an electron is added}$ $\text{- Higher electron gain enthalpy (more negative value) corresponds to higher electron affinity}$ $\text{- The order O} < \text{S} < \text{F} < \text{Cl represents increasing electron affinity}$ $\text{Key factors affecting the order:}$ $\text{1. Group 17 elements (F, Cl) have higher electron affinity than Group 16 elements (O, S)}$ $\text{2. Within Group 17: Cl} > \text{F due to electron repulsion in small F atom}$ $\text{3. Within Group 16: S} > \text{O due to larger size of S reducing electron repulsion}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}