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Current Question (ID: 7957)

Question:

$\text{The lone pairs of electrons can be defined as:}$

Options:

1. $\text{Electron pairs that participate in bonding.}$
2. $\text{Electron pairs that do not participate in bonding.}$ (Correct)
3. $\text{Electron pairs that are present in inner most shell.}$
4. $\text{Electron pairs that are present in valence shell of ions.}$

Solution:

$\text{HINT: Lone pairs are the electron pairs that do not take part in bonding.}$\n\n$\text{Explanation:}$\n\n$\text{When two atoms combine by sharing their one or more valence electrons, a covalent bond is formed between them.}$\n\n$\text{The shared pairs of electrons present between the bonded atoms are called bond pairs.}$\n\n$\text{All valence electrons may not participate in bonding. The electron pairs that do not participate in bonding are called lone pairs of electrons.}$\n\n$\text{For example, in C}_2\text{H}_6\text{ (ethane), there are seven bond pairs but no lone pair present.}$\n\n$\text{In H}_2\text{O}, \text{there are two bond pairs and two lone pairs on the central atom (oxygen).}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}