Import Question JSON

Current Question (ID: 7961)

Question:
$\text{Which among the following does not contain a set of isoelectronic species?}$
Options:
  • 1. $\text{SO}_3^{2-}\text{, CO}_3^{2-}\text{, NO}_3^-$ (Correct)
  • 2. $\text{CN}^-\text{, N}_2\text{, CO}$
  • 3. $\text{BO}_3^{3-}\text{, CO}_3^{2-}\text{, NO}_3^-$
  • 4. $\text{PO}_4^{3-}\text{, SO}_4^{2-}\text{, ClO}_4^-$
Solution:
$\text{HINT: Isoelectronic species are those ions or compounds which has an equal number of electrons.}$\n\n$\text{Explanation:}$\n\n$\text{STEP 1:}$\n\n$\text{Calculating the total number of electrons for each set:}$\n\n$\text{Set 1: SO}_3^{2-}\text{, CO}_3^{2-}\text{, NO}_3^-\text{ have 42, 32, 32 electrons respectively}$\n\n$\text{Set 2: CN}^-\text{, N}_2\text{, CO have 14 electrons in all}$\n\n$\text{Set 3: BO}_3^{3-}\text{, CO}_3^{2-}\text{, NO}_3^-\text{ have 32 electrons in all}$\n\n$\text{Set 4: PO}_4^{3-}\text{, SO}_4^{2-}\text{, ClO}_4^-\text{ have 50 electrons in all}$\n\n$\text{STEP 2:}$\n\n$\text{As SO}_3^{2-}\text{, CO}_3^{2-}\text{ and NO}_3^-\text{ have 42, 32, 32 electrons respectively, that is, SO}_3^{2-}\text{ is not isoelectronic.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}