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Current Question (ID: 7965)

Question:

$\text{Which pair of ions from the following list do not constitute an iso-electronic pair?}$

Options:

1. $\text{Mn}^{2+}, \text{Fe}^{3+}$
2. $\text{Fe}^{2+}, \text{Mn}^{2+}$ (Correct)
3. $\text{O}^{2-}, \text{F}^{-}$
4. $\text{Na}^{+}, \text{Mg}^{2+}$

Solution:

$\text{HINT: Isoelectronic species have the same number of electrons.}$ $\text{Explanation:}$ | Ions | Electronic configuration | Number of electrons | |---|---|---| | $\text{Mn}^{+2}$ | $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5$ | $23$ | | $\text{Fe}^{+3}$ | $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5$ | $23$ | | $\text{Fe}^{+2}$ | $1s^2 2s^2 2p^6 3s^2 3p^6 3d^6$ | $24$ | | $\text{O}^{2-}$ | $1s^2 2s^2 2p^6$ | $10$ | | $\text{F}^{-}$ | $1s^2 2s^2 2p^6$ | $10$ | | $\text{Na}^{+}$ | $1s^2 2s^2 2p^6$ | $10$ | | $\text{Mg}^{+2}$ | $1s^2 2s^2 2p^6$ | $10$ | $\text{Fe}^{2+}$ $\text{has 24 electrons. }$ $\text{Mn}^{2+}$ $\text{has 23, hence they are not an iso-electronic pair.}$ $\text{All other pairs are isoelectronic.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}