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Current Question (ID: 7977)

Question:

The electronic configurations of the elements $\text{A}$, $\text{B}$, and $\text{C}$ are given below. $\text{A} = 1s^2 2s^2 2p^6$ $\text{B} = 1s^2 2s^2 2p^6 3s^2 3p^3$ $\text{C} = 1s^2 2s^2 2p^6 3s^2 3p^5$ The stable form of $\text{A}$ may be represented by the formula:

Options:

1. $\text{A}$
2. $\text{A}_2$
3. $\text{A}_3$
4. $\text{A}_4$

Solution:

$\text{HINT: Noble gas does not form diatomic molecule.}\n\n\text{Explanation:}\n\n\text{STEP 1 :}\n\n\text{The given electronic configuration shows that A represents noble gas because its octet is complete.}\n\n\text{A is neon which has 10 atomic number. Noble gas is non reactive.}\n\n\text{STEP 2:}\n\n\text{So, A cannot form }\text{A}_2\text{, }\text{A}_3 \text{ and } \text{A}_4\text{. Hence, Stable form of A is A.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}