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Current Question (ID: 7981)

Question:

Most covalent compound among the following is :

Options:

1. $\text{AlF}_3$
2. $\text{AlCl}_3$
3. $\text{AlBr}_3$
4. $\text{AlI}_3$ (Correct)

Solution:

$\text{HINT: Use the concept of Fajan's Rule}\n\n\text{Explanation:}\n\n\text{STEP 1: For most covalent compound -}\n\n\text{1. Cation should be smaller.}\n\n\text{2. Charge on cation should be high.}\n\n\text{3. EA/EN of nonmetal should be low.}\n\n\text{STEP 2:}\n\n\text{The electronegativity difference between Al and I is minimum thus it is most covalent.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}