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Current Question (ID: 7982)

Question:
The correct order of covalent bond character among $\text{LiCl}$, $\text{BeCl}_2$, $\text{BCl}_3$ and $\text{CCl}_4$, is:
Options:
  • 1. $\text{LiCl} < \text{BeCl}_2 > \text{BCl}_3 > \text{CCl}_4$
  • 2. $\text{LiCl} > \text{BeCl}_2 < \text{BCl}_3 < \text{CCl}_4$
  • 3. $\text{LiCl} < \text{BeCl}_2 < \text{BCl}_3 < \text{CCl}_4$ (Correct)
  • 4. $\text{LiCl} > \text{BeCl}_2 > \text{BCl}_3 > \text{CCl}_4$
Solution:
$\text{HINT: Covalent character is directly proportional to the oxidation state of the central atom.}$ $\text{Explanation:}$ $\text{The oxidation state of the central atom in the given compounds are as follows:}$ $\text{LiCl; Li oxidation state is } +1$ $\text{BeCl}_2\text{; Be oxidation state is } +2$ $\text{BCl}_3\text{; B oxidation state is } +3$ $\text{CCl}_4\text{; C oxidation state is } +4$ $\text{As the oxidation state of the central atom increases, the covalent character on the compound also increases.}$ $\text{The electronegative difference between the central atom and the side atom decreases, the covalent character increases.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}