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Current Question (ID: 7983)

Question:
Among the following, the maximum covalent character is shown by which compound:
Options:
  • 1. $\text{MgCl}_2$
  • 2. $\text{FeCl}_2$
  • 3. $\text{AlCl}_3$ (Correct)
  • 4. $\text{SnCl}_2$
Solution:
$\text{HINT: Covalent character is directly proportional to an oxidation state of the central atom.}$ $\text{Explanation:}$ $\text{Step 1:}$ $\text{Here } \text{AlCl}_3\text{, having maximum covalent nature as Al has maximum polarising power due to } +3\text{ charge and smallest size.}$ $\text{Greater the charge and the smaller the size of the cation, the larger the charge density. Thus, greater is the polarization of the M-Cl bond and hence, the maximum covalent character is possessed by the compound.}$ $\text{Step 2:}$ $\text{Among the given species, only } \text{AlCl}_3 \text{ possesses maximum covalent charge due to the presence of large charge density on } \text{Al}^{+3} \text{ ion.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}