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Current Question (ID: 7986)

Question:

The decreasing order of ionic character of the $\text{N-H}$, $\text{F-H}$, $\text{C-H}$, and $\text{O-H}$, is :

Options:

1. $\text{N-H} > \text{F-H} > \text{C-H} > \text{O-H}$
2. $\text{F-H} > \text{N-H} > \text{C-H} > \text{O-H}$
3. $\text{O-H} > \text{C-H} > \text{F-H} > \text{N-H}$
4. $\text{F-H} > \text{O-H} > \text{N-H} > \text{C-H}$ (Correct)

Solution:

$\text{HINT: Ionic character } \propto \text{ Electronegativity difference}$ $\text{Explanation:}$ $\text{Greater is the electronegativity difference between the two bonded atoms, greater is the ionic character.}$ $\text{Bond} \qquad \text{N-H} \qquad \text{F-H} \qquad \text{C-H} \qquad \text{O-H}$ $\text{Electronegativity difference} \qquad (3.0-2.1)=0.9 \qquad (4.0-2.1)=1.9 \qquad (2.5-2.1)=0.4 \qquad (3.5-2.1)=1.4$ $\text{Therefore, increasing order of ionic character of the given bonds is as follows}$ $\text{F-H} > \text{O-H} > \text{N-H} > \text{C-H}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}