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Current Question (ID: 7987)

Question:

The favourable factors for the formation of an ionic bond would be:

Options:

1. $1.\ \text{Low ionization enthalpy, High negative electron gain enthalpy, High lattice energy.}$ (Correct)
2. $2.\ \text{High ionization enthalpy, High electron gain enthalpy, High lattice energy.}$
3. $3.\ \text{Low ionization enthalpy, Low electron gain enthalpy, Low lattice energy.}$
4. $4.\ \text{High ionization enthalpy, Low electron gain enthalpy, High lattice energy.}$

Solution:

$\text{HINT: Ionic bonding involves the complete transfer of valence electron(s) between atoms.}$ $\text{Explanation:}$ $\text{The formation of ionic bonds depends upon the ease with which neutral atoms can lose or gain electrons. The bond formation also depends upon the lattice energy of the compound formed.}$ $\text{Hence, favorable factors for ionic bond formation are as follows:}$ $\text{(i) Low ionization enthalpy of the metal atom.}$ $\text{(ii) High electron gain enthalpy (}\Delta_{\text{eg}}\text{H) of a non-metal atom.}$ $\text{(iii) High lattice energy of the compound formed.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}