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Current Question (ID: 7992)

Question:
$\text{Which of the following compounds has a higher hydration energy than the lattice energy?}$
Options:
  • 1. $\text{BaSO}_4$ (Correct)
  • 2. $\text{MgSO}_4$
  • 3. $\text{CaSO}_4$
  • 4. $\text{SrSO}_4$
Solution:
$\text{Hydration energy depends on the size of ion.} \text{Hydration energy of sulphate decreases from top to bottom in a II}^{nd} \text{ group. Mg}^{2+} \text{ is smaller in size than other ions of that group. So, Mg}^{2+} \text{ ion is readily hydrated.} \text{MgSO}_4 \text{ has higher hydration energy than lattice energy.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}