Import Question JSON

Current Question (ID: 7993)

Question:
$\text{The incorrect order of lattice energy among the following set is:}$
Options:
  • 1. $\text{AlF}_3 > \text{MgF}_2$ (Correct)
  • 2. $\text{Li}_3\text{N} > \text{Li}_2\text{O}$
  • 3. $\text{NaCl} > \text{LiF}$
  • 4. $\text{TiC} > \text{ScN}$
Solution:
$\text{HINT: Lattice energy } \propto \frac{\text{q}^+\text{q}^-}{\text{r}} \text{Explanation:} \text{Step 1:} \text{(a).} \text{As the charge on cation is increased the lattice energy increases if the anion is the same.} \text{In the case of AlF}_3\text{, the charge on Al is +3 and in the case of MgF}_2 \text{ charge on Mg is +2. Hence, as the cation charge increases the lattice energy also increases.} \text{(b).} \text{If cation is the same, then as the charge on anion increases, the lattice energy also increases.} \text{In the case of Li}_3\text{N and Li}_2\text{O, the cation is the same that is Li}^+\text{. As anion charge increases, lattice energy also increases. Nitrogen has a -3 charge, and oxygen has a -2 charge. Hence, Li}_3\text{N lattice energy is more than Li}_2\text{O.} \text{(c).} \text{Lattice energy is inversely proportional to inter-ionic distance. In NaCl and LiF, the inter-ionic distance is less in the case of LiF than NaCl. Hence, LiF has high lattice energy than NaCl.} \text{(d).} \text{In TiC and ScN, the internuclear distance is almost the same then lattice energy is explained by the charge factor.} \text{In TiC, the charge on Ti is +4 and on C is -4, and in ScN, the charge on Sc is +3 and on N is -3. Hence, TiC has more charge than ScN. Thus, the lattice energy of TiC is more than ScN.} \text{Step 2:} \text{The incorrect order is NaCl > LiF because LiF has more lattice energy than NaCl.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}