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Current Question (ID: 8002)

Question:

The application of dipole moment is/are :

Options:

1. $\text{It is used to differentiate polar and non-polar bonds.}$
2. $\text{It is helpful in calculating the percentage ionic character of a molecule.}$
3. $\text{Both '1' and '2'}$ (Correct)
4. $\text{None of the above.}$

Solution:

$\text{HINT: Dipole moment (}\mu\text{) = charge (Q) } \times \text{ distance of separation (r)} \text{Explanation:} \text{Step 1:} \text{In heteronuclear molecules, polarization arises due to a difference in the electronegativities of the constituents of atoms. As a result, one end of the molecule acquires a positive charge while the other end becomes negative. Hence, a molecule is said to possess a dipole.} \text{Dipole moment (}\mu\text{) = charge (Q) } \times \text{ distance of separation (r) The SI unit of a dipole moment is 'esu'.} \text{1 esu = 3.335 } \times \text{ 10}^{-30}\ \text{cm} \text{Dipole moment is the measure of the polarity of a bond.} \text{Step 2:} \text{It is used to differentiate between polar and non-polar bonds since all non-polar molecules (e.g. } \text{O}_2\text{, } \text{H}_2\text{) have zero dipole moments.} \text{It is also helpful in calculating the percentage ionic character of a molecule.} \text{Therefore, both statements 1 and 2 are applications of dipole moment.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}