Import Question JSON

Current Question (ID: 8005)

Question:
The correct statement among the following for a compound having a higher dipole moment is-
Options:
  • 1. $\text{Greater will the ionic nature.}$ (Correct)
  • 2. $\text{Lesser will be the polarity.}$
  • 3. $\text{Smaller will be the ionic nature.}$
  • 4. $\text{None of the above.}$
Solution:
$\text{HINT: More is the dipole moment more is ionic nature.} \text{Explanation:} \text{STEP 1:} \text{A dipole moment is simply the measure of net polarity in a molecule. Polar molecules exhibit a large difference in electrical charge (a positive end and a negative end), otherwise known as a dipole moment.} \text{STEP 2:} \mu = \text{charge} \times \text{distance} \mu \propto \text{ionic character of covalent compound} \mu \propto \text{Polarity} \text{A higher dipole moment indicates a greater separation of charge within the molecule. This means the bond is more polar, and thus has a greater ionic character.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}