Import Question JSON

Current Question (ID: 8021)

Question:

The correct sequence of the polarity of the following molecule is a. Benzene b. Inorganic Benzene c. $\text{PCl}_3\text{F}_2$ d. $\text{PCl}_2\text{F}_3$ (Where $\text{P=polar, NP=non-polar}$)

Options:

1. $\text{a: P, b: NP, c: NP, d: P}$
2. $\text{a: NP, b: NP, c: NP, d: P}$
3. $\text{a: NP, b: P, c: NP, d: P}$ (Correct)
4. $\text{a: NP, b: P, c: P, d: NP}$

Solution:

$\text{Hint: If the dipole moment is zero, then the molecule is nonpolar.} \text{Benzene (}\text{C}_6\text{H}_6\text{) is a highly symmetrical molecule with a planar hexagonal structure. Due to its symmetry, the bond dipoles cancel each other out, resulting in a net dipole moment of zero. Therefore, benzene is non-polar.} \text{Inorganic Benzene, also known as Borazine (}\text{B}_3\text{N}_3\text{H}_6\text{), has a cyclic structure similar to benzene. However, due to the difference in electronegativity between Boron and Nitrogen atoms, there are bond dipoles. These bond dipoles do not perfectly cancel out, leading to a non-zero net dipole moment, making borazine a polar molecule.} \text{For PCl}_3\text{F}_2\text{ and PCl}_2\text{F}_3\text{, we need to consider their molecular geometries based on VSEPR theory. The central atom is Phosphorus (P), which has 5 valence electrons. It forms 5 bonds.} \text{PCl}_3\text{F}_2\text{: This molecule has a trigonal bipyramidal geometry. In this geometry, the more electronegative fluorine atoms prefer the axial positions to minimize repulsions. If the two fluorine atoms are in axial positions and three chlorine atoms are in equatorial positions, the molecule is non-polar due to symmetry and cancellation of bond dipoles.} \text{PCl}_2\text{F}_3\text{: In this molecule, for a trigonal bipyramidal geometry, the three more electronegative fluorine atoms will occupy both axial positions and one equatorial position, and the two chlorine atoms will occupy the remaining two equatorial positions. This arrangement leads to an asymmetrical distribution of bond dipoles, resulting in a net dipole moment. Therefore, PCl}_2\text{F}_3\text{ is polar.} \text{So, the correct sequence is:} \text{a. Benzene - Non-polar (NP)} \text{b. Inorganic Benzene (Borazine) - Polar (P)} \text{c. PCl}_3\text{F}_2 \text{ - Non-polar (NP)} \text{d. PCl}_2\text{F}_3 \text{ - Polar (P)} \text{Thus, the correct option is 3.}$

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}