Import Question JSON

HINT: $\text{Bond angle } \alpha \frac{1}{\text{No. of lone pairs}}$ Explanation: As the number of lone pairs of electrons on the central element increases, repulsion between those lone pairs of electrons increases, and therefore, the bond angle decreases. $\text{Molecules} \begin{tabular}{|l|l|l|} \hline \text{Molecules} & \text{No. of lone pairs} & \text{Bond angle} \\ \hline \text{CH}_4 & 0 & 109.5^\circ \\ \hline \text{NH}_3 & 1 & 107.5^\circ \\ \hline \text{H}_2\text{O} & 2 & 104.45^\circ \\ \hline \end{tabular} Based on the table: 1. The $\text{H-O-H}$ bond angle in $\text{H}_2\text{O}$ is $104.45^\circ$, and the $\text{H-C-H}$ bond angle in $\text{CH}_4$ is $109.5^\circ$. So, $104.45^\circ$ is NOT larger than $109.5^\circ$. This statement is incorrect. 2. The $\text{H-O-H}$ bond angle in $\text{H}_2\text{O}$ is $104.45^\circ$, and the $\text{H-N-H}$ bond angle in $\text{NH}_3$ is $107.5^\circ$. So, $104.45^\circ$ IS smaller than $107.5^\circ$. This statement is correct. 3. The $\text{H-C-H}$ bond angle in $\text{CH}_4$ is $109.5^\circ$, and the $\text{H-N-H}$ bond angle in $\text{NH}_3$ is $107.5^\circ$. So, $109.5^\circ$ IS larger than $107.5^\circ$. This statement is correct. 4. All the listed bond angles are greater than $90^\circ$: $109.5^\circ > 90^\circ$, $107.5^\circ > 90^\circ$, and $104.45^\circ > 90^\circ$. This statement is correct. Therefore, the incorrect statement is option 1.