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Current Question (ID: 8034)

Question:
A molecule or ion that has an unequal bond length is:
Options:
  • 1. $\text{SF}_4$ (Correct)
  • 2. $\text{SiF}_4$
  • 3. $\text{XeF}_4$
  • 4. $\text{BF}_4^-$
Solution:
HINT: $\text{Trigonal bipyramidal geometry has an unequal bond length.}$ Explanation: The bipyramidal geometry structures contain unequal bond length that is, $\text{sp}^3\text{d} = \text{trigonal bipyramidal}$ $\text{sp}^3\text{d}^3 = \text{pentagonal bipyramidal}$ The hybridization of given compounds are: $\text{SiF}_4$: $\frac{4+4}{2} = \text{sp}^3 = \text{tetrahedral}$ $\text{BF}_4^-$: $\frac{3+4+1}{2} = \text{sp}^3$ $\text{SF}_4$: $\frac{6+4}{2} = 5 = \text{sp}^3\text{d}$ $\text{SF}_4$ has trigonal bipyramidal geometry (seesaw shape) due to the presence of one lone pair of electrons on the central sulfur atom, which causes distortions from the ideal trigonal bipyramidal geometry. In a trigonal bipyramidal geometry, the axial bonds are longer than the equatorial bonds, leading to unequal bond lengths. Here, $\text{SF}_4$ has trigonal bipyramidal geometry and $\text{SF}_4$ is the correct answer.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}