Import Question JSON

HINT: $\text{Bond angle totally depends on hybridization.}$ Explanation: $\begin{tabular}{|l|l|l|l|} \hline \text{Molecule} & \text{Hybridization} & \text{Repulsion} & \text{Bond angle} \\ \hline \text{SO}_2 & \text{sp}^2 & \text{lp-bp, bp-bp} & 119^\circ \\ \hline \text{H}_2\text{O} & \text{sp}^3 & \text{lp-lp, bp-bp, lp-bp} & 104.5^\circ \\ \hline \text{H}_2\text{S} & \text{No hybridization} & & 92^\circ \\ \hline \text{NH}_3 & \text{sp}^3 & \text{lp-bp, bp-bp} & 107^\circ \\ \hline \end{tabular}$ Among the given molecules, $\text{H}_2\text{S}$ has the smallest bond angle of $92^\circ$. This is because for elements from period 3 and beyond (like S in $\text{H}_2\text{S}$), the bond angles tend to be closer to $90^\circ$ due to negligible hybridization and the involvement of p-orbitals in bonding. This phenomenon is known as Drago's Rule. The lone pair repulsion in $\text{H}_2\text{S}$ is also higher than in $\text{H}_2\text{O}$ due to the larger size of the sulfur atom, which pushes the bonding pairs closer. Hence, option third is the answer.