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Current Question (ID: 8044)

Question:
$ ext{XeF}_2 \text{ is isostructural with :}$
Options:
  • 1. $ ext{TeF}_2$
  • 2. $ ext{ICl}_2^{-}$ (Correct)
  • 3. $ ext{SbCl}_3$
  • 4. $ ext{BCl}_3$
Solution:
$ ext{HINT: Isostructural compounds/ions have the same shape and hybridization.}$ $\text{Explanation:}$ $\text{STEP 1 : The hybridization of Xe in XeF}_2 \text{ is } ext{sp}^3 ext{d} \text{ and the shape of the compound is linear.}$ $\text{The shape of } ext{XeF}_2 \text{ is as follows:}$ $\text{STEP 2:}$ $\text{The hybridization of Te in TeF}_2 \text{ is } ext{sp}^3. \text{ The shape of the compound is bent.}$ $\text{The hybridization of Sb in SbCl}_3 \text{ is } ext{sp}^3. \text{ The shape of the compound is trigonal pyramidal.}$ $\text{The hybridization of B in BCl}_3 \text{ is } ext{sp}^2. \text{ The shape of the compound is trigonal planar.}$ $\text{But in the case of } ext{ICl}_2^{-}, \text{ I hybridization is } ext{sp}^3 ext{d} \text{ and shape is also linear.}$ $\text{STEP 3: Thus, XeF}_2 \text{ is isostructural with } ext{ICl}_2^{-}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}