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Current Question (ID: 8051)

Question:

$\text{The geometry and the dipole moment of } \text{H}_2\text{S is:}$

Options:

1. $\text{Angular (distorted tetrahedral) and non-zero.}$ (Correct)
2. $\text{Angular and zero.}$
3. $\text{Linear and zero.}$
4. $\text{Linear and non-zero.}$

Solution:

$\text{HINT : } \text{H}_2\text{S is angular molecule.}$ $\text{Explanation:}$ $\text{Calculate the hybridization of } \text{H}_2\text{S molecule}$ $\text{H}_2\text{S} = \frac{6+2}{2} = 4 = sp^3 \text{ Hybridization}$ $\text{Correct option (1) angular and non-zero}$ $\text{Molecular geometry: angular, Dipole moment: non-zero}$ $\text{H}_2\text{S molecule has an angular geometry because it has two lone pairs of electrons that make the molecule bend.}$ $\text{The dipole moment is not zero. This is because sulphur is more electronegative than hydrogen, making the molecule slightly polar. The structure of } \text{H}_2\text{S is as follows:}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}