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Current Question (ID: 8053)

Question:
$\text{Which of the following pairs of species have similar shapes?}$
Options:
  • 1. $\text{PCl}_3, \text{NH}_3$
  • 2. $\text{CF}_4, \text{SF}_4$
  • 3. $\text{PbCl}_2, \text{CO}_2$
  • 4. $\text{PF}_5, \text{IF}_5$
Solution:
$\text{HINT: Compound having same hybridization has same shape.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{Molecules} \quad \text{Hybridisation} \quad \text{Shape}$ $\text{PCl}_3 \quad sp^3 \quad \text{Trigonal Pyramidal}$ $\text{NH}_3 \quad sp^3 \quad \text{Trigonal Pyramidal}$ $\text{CF}_4 \quad sp^3 \quad \text{Tetrahedral}$ $\text{SF}_4 \quad sp^3d \quad \text{See-saw}$ $\text{PbCl}_2 \quad sp^2 \quad \text{Bent}$ $\text{CO}_2 \quad sp^2 \quad \text{Linear}$ $\text{PF}_5 \quad sp^3d \quad \text{Trigonal Bipyramidal}$ $\text{IF}_5 \quad sp^3d^2 \quad \text{Square Pyramidal}$ $\text{STEP 2:}$ $\text{PCl}_3 \text{ and } \text{NH}_3, \text{ both have same hybridization that is } sp^3. \text{ Therefore, both have same shape.}$ $\text{Both have pyramidal structure.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}