Import Question JSON

Current Question (ID: 8056)

Question:
Match the compounds of $\text{Xe}$ in column $\text{I}$ with the molecular structure in column $\text{II}.$ $\text{Column-I}\hspace{20mm}\text{Column-II}$ $(\text{a})\text{ }\text{XeF}_2\hspace{20mm}(\text{i})\text{ Square planar}$ $(\text{b})\text{ }\text{XeF}_4\hspace{20mm}(\text{ii})\text{ Linear}$ $(\text{c})\text{ }\text{XeO}_3\hspace{20mm}(\text{iii})\text{ Square pyramidal}$ $(\text{d})\text{ }\text{XeOF}_4\hspace{18mm}(\text{iv})\text{ Pyramidal}$
Options:
  • 1. (a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
  • 2. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
  • 3. (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
  • 4. (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii) (Correct)
Solution:
$\text{HINT: Molecular structure will depend on the lone pairs.}$ $\text{Explanation:}$ $\text{Molecule}\hspace{10mm}\text{Hybridisation}\hspace{10mm}\text{Molecular structure}$ $\text{XeF}_2\hspace{18mm}\text{sp}^3\text{d}\hspace{20mm}\text{Linear}$ $\text{XeF}_4\hspace{18mm}\text{sp}^3\text{d}^2\hspace{14mm}\text{Square planar}$ $\text{XeO}_3\hspace{18mm}\text{sp}^3\hspace{20mm}\text{Pyramidal}$ $\text{XeOF}_4\hspace{16mm}\text{sp}^3\text{d}^2\hspace{12mm}\text{Square pyramidal}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}