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Current Question (ID: 8068)

Question:
From the following pairs, the two species that are not isostructural are :
Options:
  • 1. $\text{PF}_5\text{ and BrF}_5$ (Correct)
  • 2. $\text{PCl}_4^{+}\text{ and SiCl}_4$
  • 3. $\text{CO}_3^{2-}\text{ and NO}_3^{-}$
  • 4. $\text{AlF}_6^{3-}\text{ and SF}_6$
Solution:
$\text{HINT: Isostructural compounds have the same hybridization and shape.}\n\n\text{Explanation:}\n\text{STEP 1:}\n\begin{tabular}{|l|l|l|}\n\hline\n\text{Molecules} & \text{Hybridisation} & \text{Molecular structure} \\\n\hline\n\text{PF}_5 & \text{sp}^3\text{d} & \text{Trigonal Bipyramidal} \\\n\hline\n\text{BrF}_5 & \text{sp}^3\text{d}^2 & \text{Square Pyramidal} \\\n\hline\n\text{PCl}_4^{+}\text{ and SiCl}_4 & \text{sp}^3 & \text{Tetrahderal} \\\n\hline\n\text{CO}_3^{2-}\text{ and NO}_3^{-} & \text{sp}^2 & \text{Trigonal Planar} \\\n\hline\n\text{AlF}_6^{3-}\text{ and SF}_6 & \text{sp}^3\text{d}^2 & \text{Octahedral} \\\n\hline\n\end{tabular}\n\n\text{STEP 2:}\n\n\text{In option 1, both compounds have different hybridization and shape . So, }\n\text{PF}_5\text{ and BrF}_5\text{ are not isostructural.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}