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$\text{HINT: Compound having } \text{sp}^2 \text{ hybridization is planar in nature. and difference of electronegativity will create polarity}$ $\text{Explanation:}$ $\text{STEP 1: The steric number formula is as follows:}$ $\text{S} = \frac{1}{2} \text{(V + M - C + A)}$ $\text{V = valence electron of central atom}$ $\text{M = monovalent atom}$ $\text{C = positive charge on compound}$ $\text{A = negative charge on compound}$ $\text{STEP 2: The steric number for the given compound as follows:}$ $\begin{array}{|l|l|l|l|l|} \hline \text{Molecules} & \text{Steric number} & \text{Hybridisation} & \text{Structure} & \text{Polarity} \\ \hline \text{1. } \text{TeCl}_4 & 5 & \text{sp}^3\text{d} & \text{See-saw} & \text{Polar} \\ \hline \text{2. } \text{SO}_2 & 3 & \text{sp}^2 & \text{Planar} & \text{Polar} \\ \hline \text{3. } \text{SF}_6 & 6 & \text{sp}^3\text{d}^2 & \text{Octahedral} & \text{Non Polar} \\ \hline \text{4. } \text{XeF}_2 & 5 & \text{sp}^3\text{d} & \text{Linear} & \text{polar} \\ \hline \end{array}$ $\text{sp}^3\text{d is hybridisation of } \text{XeF}_2 \text{, so F will be in different plane than Xe, it can be called as linear, but not planar}$ $\text{Hence, } \text{SO}_2 \text{ hybridization is } \text{sp}^2\text{,S and O is in the same plane at 119 degree angle, thus is planar and due to one lone pair, it is polar also.}$