Import Question JSON

HINT: Bond order $\alpha$ Stability Explanation: The electronic configuration of a given molecule/ion according to MOT is as follows: 1. Electronic configuration of $\text{O}_2$ (16 electrons) = $\sigma_{1s}^2$, $\sigma_{1s}^{*2}$, $\sigma_{2s}^2$, $\sigma_{2s}^{*2}$, $\sigma_{2pz}^2$, $\pi_{2px}^2 \approx \pi_{2py}^2$, $\pi_{2px}^{*1} \approx \pi_{2py}^1$ Bond order = $\frac{1}{2}$ $(\text{N}_b - \text{N}_a)$ = $\frac{1}{2}$ $(10 - 6)$ = $2$ 2. Electronic configuration of $\text{O}_2^+$ (15 electrons) = $\sigma_{1s}^2$, $\sigma_{1s}^{*2}$, $\sigma_{2s}^2$, $\sigma_{2s}^{*2}$, $\sigma_{2pz}^2$, $\pi_{2px}^2 \approx \pi_{2py}^2$, $\pi_{2px}^{*1} \approx \pi_{2py}^0$ Bond order = $\frac{1}{2}$ $(\text{N}_b - \text{N}_a)$ = $\frac{1}{2}$ $(10 - 5)$ = $2.5$ 3. Electronic configuration of $\text{O}_2^-$ (17 electrons) = $\sigma_{1s}^2$, $\sigma_{1s}^{*2}$, $\sigma_{2s}^2$, $\sigma_{2s}^{*2}$, $\sigma_{2pz}^2$, $\pi_{2px}^2 \approx \pi_{2py}^2$, $\pi_{2px}^{*2} \approx \pi_{2py}^1$ Bond order = $\frac{1}{2}$ $(\text{N}_b - \text{N}_a)$ = $\frac{1}{2}$ $(10 - 7)$ = $1.5$ 4. Electronic configuration of $\text{O}_2^{2-}$ (18 electrons) = $\sigma_{1s}^2$, $\sigma_{1s}^{*2}$, $\sigma_{2s}^2$, $\sigma_{2s}^{*2}$, $\sigma_{2pz}^2$, $\pi_{2px}^2 \approx \pi_{2py}^2$, $\pi_{2px}^{*2} \approx \pi_{2py}^2$ Bond order = $\frac{1}{2}$ $(\text{N}_b - \text{N}_a)$ = $\frac{1}{2}$ $(10 - 8)$ = $1$ Thus, the order of bond order is directly proportional to the relative stability. The order is: $\text{O}_2^+ > \text{O}_2 > \text{O}_2^- > \text{O}_2^{2-}$