Import Question JSON

Current Question (ID: 8086)

Question:
The specie with the shortest bond length is:
Options:
  • 1. $\text{O}_2^+$
  • 2. $\text{O}_2^-$
  • 3. $\text{O}_2^{2-}$
  • 4. $\text{O}_2^{2+}$ (Correct)
Solution:
HINT: Bond order $\propto \frac{1}{\text{Bond length}}$ Explanation: The bond order relation with bond length is as follows: Bond order $\propto \frac{1}{\text{Bond length}}$ Bond orders of $\text{O}_2^+$, $\text{O}_2^-$, $\text{O}_2^{2-}$ and $\text{O}_2^{2+}$ are respectively $2.5$, $1.5$, $1$ and $3$. Hence $\text{O}_2^{2+}$ is the shortest in bond length because it has the highest bond order.

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}