Import Question JSON

Current Question (ID: 10497)

Question:

$\text{The surface tension of a liquid is 5 N m}^{-1}\text{. If a film is held on a ring of area 0.02 m}^2\text{, then its total surface energy is:}$

Options:

1. $3 \times 10^{-2} \text{ J}$
2. $2 \times 10^{-1} \text{ J}$
3. $3 \times 10^{-3} \text{ J}$
4. $10^{-1} \text{ J}$

Solution:

$\text{Hint: Surface energy = Surface tension × area}$ $\text{Step 1: Find the number of surfaces of the film held on the ring.}$ $\text{A film will be formed on both sides of the ring. So it will have two surfaces.}$ $\text{Step 2: Find the surface energy of the ring.}$ $\text{Surface energy,}$ $E = S \times 2 \times A$ $= 5 \times 2 \times 0.02$ $= 0.2 \text{ J}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}