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Current Question (ID: 10517)

Question:
$\text{The area of cross-section of the wider tube shown in the figure is 800 cm}^2\text{. If a mass of 12 kg is placed on the massless piston, then the difference in heights h of the levels of water in the two tubes will be:}$
Options:
  • 1. $\text{10 cm}$
  • 2. $\text{6 cm}$
  • 3. $\text{15 cm}$
  • 4. $\text{2 cm}$
Solution:
$\text{Pressure should be same on both sides.}$ $P = \frac{12g}{800} \times 10^{-4} = h \times 10^3 \times g$ $h = \frac{12}{80} \text{ m} = 15 \text{ cm}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}