Import Question JSON

Current Question (ID: 10530)

Question:

$\text{The velocity of kerosene oil in a horizontal pipe is 5 m/s. If } g = 10 \text{ m/s}^2\text{, then the velocity head of oil will be:}$

Options:

1. $1.25 \text{ m}$
2. $12.5 \text{ m}$
3. $0.125 \text{ m}$
4. $125 \text{ m}$

Solution:

$\text{The velocity head is calculated using the formula:}$ $h = \frac{v^2}{2g}$ $\text{Given:}$ $v = 5 \text{ m/s}$ $g = 10 \text{ m/s}^2$ $\text{Substituting the values:}$ $h = \frac{(5)^2}{2 \times 10} = \frac{25}{20} = 1.25 \text{ m}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}