Import Question JSON

Current Question (ID: 10548)

Question:

$\text{In a capillary tube, pressure below the curved surface of the water will be:}$

Options:

1. $\text{equal to atmospheric pressure.}$
2. $\text{equal to upper side pressure.}$
3. $\text{more than upper side pressure.}$
4. $\text{lesser than upper side pressure.}$

Solution:

$\text{In a capillary tube, water forms a concave meniscus due to surface tension. This curvature creates a pressure difference across the interface.}$ $\text{Due to the concave shape, the pressure inside the curved surface (i.e., below the curved surface of the water) is less than the pressure outside the curved surface (i.e., the upper side pressure, which is essentially atmospheric pressure if the top is open to the atmosphere). This pressure difference is what allows the water to rise in the capillary tube.}$ $\text{Therefore, the correct answer is 4. lesser than upper side pressure.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}