Import Question JSON

Current Question (ID: 10551)

Question:

$\text{The bonding present in nitrogen molecules is:}$

Options:

1. $p\pi - p\pi$ (Correct)
2. $p\pi - d\pi$
3. $d\pi - d\pi$
4. $\text{Only sigma bond}$

Solution:

$\text{HINT: N}_2 \text{ molecule contains sigma bond and pie bond.}$ $\text{Explanation:}$ $\text{STEP 1: Nitrogen is chemically less reactive. This is because of the high stability of its molecule, N}_2\text{. In N}_2\text{, the two nitrogen atoms form a triple bond.}$ $\text{This triple bond has very high bond strength, which is very difficult to break.}$ $\text{STEP 2: It is because of nitrogen's small size that it is able to form p}\pi\text{-p}\pi \text{ bonds with itself. This property is not exhibited by atoms such as phosphorus.}$ $\text{[The solution includes a molecular orbital diagram showing the formation of sigma and pi bonds in N}_2 \text{ molecule through overlap of p orbitals]}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}