Import Question JSON

Current Question (ID: 10554)

Question:

$\text{Match the name of process given in Column I with the name of compound given in Column II and mark the correct option.}$ $\text{Column I:}$ $\text{(a) Pure nitrogen}$ $\text{(b) Haber process}$ $\text{(c) Contact process}$ $\text{(d) Deacons process}$ $\text{Column II:}$ $\text{(i) Chlorine}$ $\text{(ii) Sulphuric acid}$ $\text{(iii) Ammonia}$ $\text{(iv) Sodium azide or Barium azide}$

Options:

1. $\text{(a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)}$ (Correct)
2. $\text{(a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)}$
3. $\text{(a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)}$
4. $\text{(a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)}$

Solution:

$\text{Hint: Haber process is used for the manufacturing of nitrogen}$ $\text{a. Haber process used for manufacturing of Ammonia}$ $\text{b. Pure nitrogen is obtained in small amounts by heating sodium or barium azides in a vacuum.}$ $\text{Ba}(\text{N}_3)_2 \rightarrow 3\text{N}_2 + \text{Ba}$ $\text{c. Contact process is used for the production of sulphuric acid}$ $\text{d. Deacon's process is used for the manufacturing of chlorine}$ $4\text{HCl} + \text{O}_2 \xrightarrow{700\text{K}} 2\text{H}_2\text{O} + \text{Cl}_2$ $\text{The correct option is the first option.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}