Import Question JSON

Current Question (ID: 10562)

Question:

$\text{Ammonium dichromate and barium azide on heating gives:}$

Options:

1. $\text{N}_2 \text{ in both cases.}$ (Correct)
2. $\text{N}_2 \text{ with ammonium dichromate and NO with barium azide.}$
3. $\text{N}_2\text{O} \text{ with ammonium dichromate and } \text{N}_2 \text{ with barium azide.}$
4. $\text{N}_2\text{O} \text{ with ammonium dichromate and } \text{NO}_2 \text{ with barium azide.}$

Solution:

$\text{Hint: Both forms } \text{N}_2 \text{ on heating.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{Ammonium dichromate decomposes on heating to produce nitrogen gas, water vapor (gaseous due to the temperature of the reaction), and solid chromium(III) oxide.}$ $\text{Barium azide is used to prepare magnesium, sodium, lithium, rubidium, and zinc azides. On heating, at high temperature the barium azide undergoes thermal decomposition.}$ $\text{The thermal decomposition of barium azide produces elemental barium with nitrogen gas.}$ $\text{STEP 2:}$ $\text{Thus, on heating ammonium dichromate and barium azide it produces } \text{N}_2 \text{ gas separately.}$ $\text{The reactions can be represented as :}$ $1. (\text{NH}_4)_2 \text{Cr}_2 \text{O}_7 \xrightarrow{\Delta} \text{N}_2 + 4\text{H}_2\text{O} + \text{Cr}_2 \text{O}_3$ $2. \text{Ba}(\text{N}_3)_2 \rightarrow \text{Ba} + 3\text{N}_2$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}