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Current Question (ID: 10564)

Question:
$\text{The correct increasing order of basic strength of hydrides:}$
Options:
  • 1. $\text{BiH}_3 \simeq \text{SbH}_3 < \text{AsH}_3 < \text{PH}_3 < \text{NH}_3$ (Correct)
  • 2. $\text{BiH}_3 > \text{NH}_3 > \text{PH}_3 > \text{SbH}_3 > \text{AsH}_3$
  • 3. $\text{SbH}_3 < \text{AsH}_3 < \text{PH}_3 < \text{NH}_3 < \text{BiH}_3$
  • 4. $\text{AsH}_3 > \text{NH}_3 > \text{PH}_3 > \text{SbH}_3 > \text{BiH}_3$
Solution:
$\text{HINT: Basic strength of group 15 hydrides decreases down the group.}$ $\text{Explanation:}$ $\text{Basic strength depends upon the electron density of atom.}$ $\text{On moving from nitrogen to bismuth, the size of the atom increases while the electron density on the atom decreases.}$ $\text{As the electron density of the lone pair is spread over a greater volume and is consequently more diffuse, the lone pair of electrons becomes less nucleophilic, less basic.}$ $\text{Thus, the basic strength decreases down the group.}$ $\text{So, the order of basic strength is : } \text{BiH}_3 \simeq \text{SbH}_3 < \text{AsH}_3 < \text{PH}_3 < \text{NH}_3$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}