Import Question JSON

Current Question (ID: 10568)

Question:

$\text{Which of the following statements is true?}$

Options:

1. $\text{All three N - O bond lengths in HNO}_3 \text{ are equal.}$
2. $\text{All P - Cl bond lengths in PCl}_5 \text{ molecule in gaseous state are equal.}$
3. $\text{P}_4 \text{ molecules in white phosphorus have angular strain. Therefore, white phosphorus is very reactive.}$ (Correct)
4. $\text{PCl}_5 \text{ is ionic in a solid state in which the anion is tetrahedral and the cation is octahedral.}$

Solution:

$\text{HINT: In HNO}_3\text{, all the three N-O bond lengths are unequal.}$ $\text{Explanation:}$ $\text{(1) The Lewis structure of nitric acid has a resonating structure. It has a } \pi \text{ bond, covalent bond and a dative bond between N and O but no ionic bond is present. The structure clearly shows that it has four single bonds and one } \pi \text{ bond. All the three N - O bond lengths in HNO}_3 \text{ are not equal.}$ $\text{(2) All P - Cl bond lengths in PCl}_5 \text{ molecule in gaseous state are not equal. Axial bond is longer than equatorial bond.}$ $\text{(3) P}_4 \text{ molecule in white phosphorus have angular strain therefore white phosphorus is very reactive.}$ $\text{(4) PCl}_5 \text{ is ionic in solid state in which cation is tetrahedral and anion is octahedral. In solid state it exists as: Cation - [PCl}_4\text{]}^+ \text{ and Anion - [PCl}_6\text{]}^-$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}