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Current Question (ID: 10572)

Question:
$\text{The condition that does not exist in the Haber process for the manufacturing of ammonia is:}$
Options:
  • 1. $\text{Pressure (around } 200 \times 10^5 \text{ Pa)}$
  • 2. $\text{Temperature (700 K)}$
  • 3. $\text{Catalyst such as iron oxide.}$
  • 4. $\text{Presence of inert gases.}$ (Correct)
Solution:
$\text{HINT: Inert gas is not required for Haber's process.}$ $\text{Explanation:}$ $\text{Ammonia is prepared on a large scale by Haber's process.}$ $\text{Step 1:}$ $\text{The reaction is as follows:}$ $\text{N}_{2(g)} + 3\text{H}_{2(g)} \rightleftharpoons 2\text{NH}_{3(g)} \quad \Delta_r\text{H}^{\circ} = -46.1 \text{ kJ/mol}$ $\text{The optimum conditions for manufacturing ammonia are:}$ $\text{(i) Pressure (around } 200 \times 10^5 \text{ Pa)}$ $\text{(ii) Temperature (700 K)}$ $\text{(iii) Catalyst such as iron oxide with small amounts of Al}_2\text{O}_3 \text{ and K}_2\text{O}$ $\text{Step 2:}$ $\text{The diagram of Haber's process shows the industrial setup with compressor, catalyst chamber, and separation unit.}$ $\text{The resulting catalyst particles consist of a core of magnetite, encased in a shell of wüstite, which in turn is surrounded by an outer shell of metallic iron.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}