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Current Question (ID: 10574)

Question:
$\text{The false statement regarding hydrides from the 15th group is:}$
Options:
  • 1. $\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3 \text{ Thermal stability}$
  • 2. $\text{N-H} > \text{P-H} > \text{As-H} > \text{Sb-H} > \text{Bi-H E-H bond dissociation enthalpy}$
  • 3. $\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3 \text{ Reducing character}$ (Correct)
  • 4. $\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3 \text{ Basicity}$
Solution:
$\text{Hint: Reducing character} \propto \frac{1}{\text{E-H}} \text{ bond dissociation enthalpy}$ $\text{Explanation:}$ $\text{a. Thermal stability decreases gradually from NH}_3 \text{ to BiH}_3\text{. The size of the central atom increases from N to Bi, therefore, the tendency to form a stable covalent bond with small hydrogen atoms decreases.}$ $\text{As the bond length increases, the bond strength decreases and therefore, thermal stability decreases.}$ $\text{b. The size of the central atom increases from N to Bi, therefore, the tendency to form a stable covalent bond with small hydrogen atoms decreases. As the bond length increases, the bond strength decreases and therefore, bond dissociation enthalpy decreases.}$ $\text{c. Reducing character} \propto \frac{1}{\text{E-H}} \text{ bond dissociation enthalpy}$ $\text{The size of the central atom increases from N to Bi, therefore, the tendency to form a stable covalent bond with small hydrogen atoms decreases.}$ $\text{As the bond length increases, the bond strength decreases and therefore bond dissociation enthalpy decreases.}$ $\text{Hence, the correct reducing character is}$ $\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3$ $\text{d. The basic character decreases from NH}_3 \text{ to BiH}_3\text{. The basic nature is due to the presence of lone pair of electrons on the central atom. NH}_3 \text{ is the strongest electron-pair donor due to its small size as the electron density of the electron pair is concentrated over a small region.}$ $\text{As the size increases the electron density gets diffused over a large region and hence the ability to donate the electron pair (basic nature) decreases.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}