Import Question JSON

Current Question (ID: 10575)

Question:

$\text{Nitrogen dioxide is paramagnetic in a gaseous state but diamagnetic in solid because:}$

Options:

1. $\text{NO}_2 \text{ exists as a dimer in a gaseous as well as solid state.}$
2. $\text{NO}_2 \text{ exists as a monomer in a gaseous as well as solid state.}$
3. $\text{NO}_2 \text{ exists as a dimer in a gaseous state and it becomes a monomer in solid state.}$
4. $\text{NO}_2 \text{ exists as a monomer in a gaseous state and it becomes dimerized in solid state.}$ (Correct)

Solution:

$\text{HINT: } \text{NO}_2 \text{ dimerises in solid state.}$ $\text{Explanation:}$ $\text{In gaseous state, } \text{NO}_2 \text{ exists as a monomer which has one unpaired electron but in solid state, it dimerises to } \text{N}_2\text{O}_4 \text{ so no unpaired electron left.}$ $\text{i.e. The presence of an unpaired electron on nitrogen makes it very reactive. It tries to dimerize and form a stable compound as } \text{N}_2\text{O}_4 \text{ with an even number of electrons.}$ $\text{Therefore, } \text{NO}_2 \text{ is paramagnetic in gaseous state but diamagnetic in solid state.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}