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Current Question (ID: 10587)

Question:
$\text{Which of the following is true about reactivity of group 15 elements?}$
Options:
  • 1. $\text{Stability of their hydrides increases down the group.}$
  • 2. $\text{Higher oxides are acidic in nature.}$ (Correct)
  • 3. $\text{All elements form pentahalides.}$
  • 4. $\text{They do not react with metals.}$
Solution:
$\text{HINT: 15th group element reacts with metals.}$ $\text{Explanation:}$ $\text{General trends in chemical properties of the group - 15 is as follows:}$ $\text{1. The stability of hydrides decreases down the group because bond}$ $\text{dissociation energy decreases.}$ $\text{2. As the oxidation number of central atom increases the acidity is also}$ $\text{increases. Thus, } \text{N}_2\text{O}_3 \text{ is less acidic than } \text{N}_2\text{O}_5\text{.}$ $\text{Hence, higher oxides are acidic in nature.}$ $\text{3. All elements do not form pentahalides. Nitrogen does not have d orbitals;}$ $\text{thus, it will not form pentahalide. It only forms trihalides.}$ $\text{4. They react with metals and form binary compounds that exhibit a -3}$ $\text{oxidation state. For example } \text{Ca}_3\text{N}_2 \text{ and } \text{Ca}_3\text{P}_2$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}