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Current Question (ID: 10592)

Question:
$\text{Oxidation of nitrogen among the following reactions is indicated by -}$
Options:
  • 1. $\text{N}_2 \rightarrow 2\text{NH}_3$
  • 2. $\text{N}_2\text{O}_4 \rightarrow 2\text{NO}_2$
  • 3. $\text{NO}_3^- \rightarrow \text{N}_2\text{O}_5$
  • 4. $\text{NO}_2^- \rightarrow \text{NO}_3^-$ (Correct)
Solution:
$\text{Hint: Increase in oxidation state indicate oxidation.}$ $\text{Step 1:}$ $\text{Calculate the change in the oxidation state of nitrogen in every reaction.}$ $\text{1. } \text{N}_2 \rightarrow 2\text{NH}_3$ $\text{Oxidation states: } 0 \rightarrow -3$ $\text{In the given reaction, reduction takes place because the nitrogen oxidation state is decreasing.}$ $\text{2. } \text{N}_2\text{O}_4 \rightarrow 2\text{NO}_2$ $\text{Oxidation states: } +4 \rightarrow +4$ $\text{3. } \text{NO}_3^- \rightarrow \text{N}_2\text{O}_5$ $\text{Oxidation states: } +5 \rightarrow +5$ $\text{4. } \text{NO}_2^- \xrightarrow{\text{Oxidation}} \text{NO}_3^-$ $\text{Oxidation states: } +3 \rightarrow +5$ $\text{In the above reaction, the nitrogen oxidation state is increased. Hence, it is an example of an oxidation reaction.}$ $\text{Step 2:}$ $\text{Thus, option 4th is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}