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Current Question (ID: 10598)

Question:
$\text{Which of the following is in correct sequence in terms of acid nature?}$
Options:
  • 1. $\text{HClO}_2 < \text{HClO}_3 < \text{HClO}_4$
  • 2. $\text{H}_3\text{PO}_4 < \text{H}_3\text{PO}_3 < \text{H}_3\text{PO}_2$
  • 3. $\text{CH}_4 < \text{NH}_3 < \text{H}_2\text{O} < \text{HF}$
  • 4. $\text{All of the above.}$ (Correct)
Solution:
$\text{Step 1:}$ $\text{As the oxidation state of the central atom increases the acidity of the compound also increases.}$ $\text{Step 2:}$ $\text{The oxidation state of the central atoms in the given compounds is as follows:}$ $\text{HClO}_2 < \text{HClO}_3 < \text{HClO}_4$ $\text{+3} \quad \text{+5} \quad \text{+7}$ $\text{The electronegativity increases along the period. Acidity of hydrides of corresponding elements also increase with increase in electronegativity of these elements.}$ $\text{CH}_4 < \text{NH}_3 < \text{H}_2\text{O} < \text{HF}$ $\text{-4} \quad \text{-3} \quad \text{-2} \quad \text{-1}$ $\text{In the case of oxoacid of phosphorus, the above rule is not valid it is an exceptional case.}$ $\text{H}_3\text{PO}_4 < \text{H}_3\text{PO}_3 < \text{H}_3\text{PO}_2$ $\text{Phosphorous acid H}_3\text{PO}_3\text{: } 5.0 \times 10^{-2}$ $\text{Phosphoric acid H}_3\text{PO}_4\text{: } 6.9 \times 10^{-3}$ $\text{The double bonded oxygen has negative inductive effect (-I). And this electron withdrawing effect is experienced by one HH of the one -OH group in H}_3\text{PO}_2\text{. Hence it has the greatest acidic strength.}$ $\text{Similarly, the -I effect of OO is experienced by two HH of the two -OH groups in H}_3\text{PO}_3\text{, hence the electron-withdrawing effect is reduced because it is getting distributed between two groups. Hence, it has lesser acidic strength. Similarly, in H}_3\text{PO}_4\text{, it is distributed between 3 groups and so the acidic strength is the least.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}