Import Question JSON

Current Question (ID: 10605)

Question:

$\text{Which of the following statements is false?}$

Options:

1. $\text{Nitrous oxide supports combustion more vigorously than air.}$
2. $\text{Phosphorous pentaoxide dehydrates nitric acid-forming nitrogen pentaoxide.}$
3. $\text{Reactivity order of various allotropic forms of phosphorous is white > red > black.}$
4. $\text{Red phosphorous changes to white phosphorus on heating in the atmosphere of } \text{CO}_2 \text{ or coal gas at 573 K.}$ (Correct)

Solution:

$\text{Hint: White phosphorus is less stable than red phosphorus}$ $\text{1. Yes, nitrous oxide supports combustion more vigorously than air. It does not burn but supports combustion. The burning material}$ $\text{decomposes nitrous oxide into nitrogen and oxygen. The oxygen then helps in the burning. The reaction is as follows:}$ $2\text{N}_2\text{O} \rightarrow 2\text{N}_2 + \text{O}_2$ $\text{It produces one third oxygen by volume of total gas produced while air has a one-fifth volume of oxygen.}$ $\text{(2)}$ $\text{Phosphorous pentaoxide has a great affinity for water. Thus, used as a powerful dehydrating or drying agent.}$ $2\text{HNO}_3 \xrightarrow{\text{P}_2\text{O}_5} \text{HPO}_3 + \text{N}_2\text{O}_5$ $\text{(3) White phosphorus is most reactive and black phosphorus is almost inert.}$ $\text{(4) White phosphorus turns to red phosphorus on heating in the atmosphere of } \text{CO}_2 \text{ or coal gas at 573 K.}$ $\text{Hence, the correct answer is option 4th.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}