Import Question JSON

Current Question (ID: 10607)

Question:

$\text{Incorrect statement regarding } \text{PH}_3 \text{ is:}$

Options:

1. $\text{It is produced by the hydrolysis of } \text{Ca}_3\text{P}_2$
2. $\text{It gives a black ppt, } \text{Cu}_3\text{P}_2 \text{ with a } \text{CuSO}_4 \text{ solution.}$
3. $\text{It spontaneously burns in the presence of } \text{P}_2\text{H}_4$
4. $\text{It does not react with } \text{B}_2\text{H}_6$ (Correct)

Solution:

$\text{Hint: } \text{PH}_3 \text{ (Lewis base) can react with } \text{B}_2\text{H}_6 \text{ (Lewis acid).}$ $\text{Explanation:}$ $\text{By doing hydrolysis of calcium phosphide with water or dil. HCl, phosphine is obtained as a product. The reaction is as follows:}$ $\text{Ca}_3\text{P}_2 + 6\text{H}_2\text{O} \rightarrow 3\text{Ca(OH)}_2 + 2\text{PH}_3$ $\text{When phosphine is passed through copper sulphate solution, a black precipitate of cupric phosphide is formed. The reaction is as follows:}$ $3\text{CuSO}_4 + 2\text{PH}_3 \rightarrow \text{Cu}_3\text{P}_2 + 3\text{H}_2\text{SO}_4$ $\text{PH}_3 \text{ (Lewis base) can react with } \text{B}_2\text{H}_6 \text{ (Lewis acid).}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}