Import Question JSON

Current Question (ID: 10619)

Question:
$\text{Which of the following statements is true?}$
Options:
  • 1. $\text{NH}_3 \text{ is less soluble than } \text{PH}_3 \text{ in water}$
  • 2. $\text{NH}_3 \text{ is a stronger base and stronger reducing agent than } \text{PH}_3$
  • 3. $\text{NH}_3 \text{ has a higher boiling point than } \text{PH}_3 \text{ and has a lower melting point than } \text{PH}_3$
  • 4. $\text{PH}_3 \text{ is a stronger reducing agent than } \text{NH}_3 \text{ and it has lower melting critical temperature than } \text{NH}_3$ (Correct)
Solution:
$\text{NH}_3 \text{ is highly soluble in water but other hydrides are less soluble because } \text{NH}_3 \text{ show hydrogen bonding with water.}$ $\text{Down the group reducing nature increases. This shows that bond strength M-H decreases as the electronegativity of M decreases. } \text{NH}_3 \text{ is a weak reducing agent while } \text{AsH}_3\text{, } \text{SbH}_3 \text{ and } \text{BiH}_3 \text{ are powerful reducing agents.}$ $\text{In } \text{NH}_3\text{, molecules are associated with hydrogen bonding and thus its boiling point is comparatively high in comparison to } \text{PH}_3 \text{ and } \text{AsH}_3 \text{ where no hydrogen bonding is present.}$ $\text{The basic character decreases from } \text{NH}_3 \text{ to } \text{BiH}_3\text{. The basic nature is due to the presence of lone pair of electrons on the central atom. } \text{NH}_3 \text{ is the strongest electron-pair donor due to its small size' as the electron density of the electron pair is concentrated over a small region. As the size increases the electron density gets diffused over a large region and hence the ability to donate the electron pair (basic nature) decreases.}$ $\text{Hence, option 4th is the correct answer.}$

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}