Import Question JSON

« Back to Question List Edit Question »

Current Question (ID: 10636)

Question:
$\text{Match the items in Columns I and II and mark the correct option.}$ $\textbf{Column I} \qquad \qquad \qquad \textbf{Column II}$ $\text{A. H}_2\text{SO}_4 \qquad \qquad \qquad \text{1. Highest electron affinity}$ $\text{B. CCl}_3\text{NO}_2 \qquad \qquad \qquad \text{2. Chalcogen}$ $\text{C. Cl}_2 \qquad \qquad \qquad \qquad \text{3. Tear gas}$ $\text{D. Sulphur} \qquad \qquad \qquad \text{4. Storage batteries}$
Options:
  • 1. $\text{A-4, B-3, C-1, D-2}$ (Correct)
  • 2. $\text{A-3, B-4, C-1, D-2}$
  • 3. $\text{A-4, B-1, C-2, D-3}$
  • 4. $\text{A-2, B-1, C-3, D-4}$
Solution:
$\textbf{HINT:} \text{Group 16}^{\text{th}} \text{ elements are called chalcogen.}$$ $\textbf{Explanation:}$$ $\text{1.) H}_2\text{SO}_4 \text{ is used in storage batteries. Battery acid is sulfuric acid that has}$ $\text{been diluted with water to attain a 38\% concentration level.}$$ $\text{The sulphuric acid is used as an electrolyte in lead-acid batteries. During the}$ $\text{discharge of lead-acid batteries, the lead sulphate is formed on both the}$ $\text{electrodes because of the reaction with sulphuric acid.}$$ $\text{When the battery charges, lead sulphate gets converted to lead and lead}$ $\text{oxide by releasing the sulphuric acid into the electrolyte.}$$ $\text{2.) CCl}_3\text{NO}_2 \text{ (Chloropicrin) is known as tear gas. Chloropicrin (PS) is an}$ $\text{irritant with characteristics of a tear gas. Chloropicrin (PS) has an intensely}$ $\text{irritating odor.}$$ $\text{3.) Cl}_2 \text{ has the highest electron gain enthalpy. This is because the}$ $\text{interelectronic repulsions in chlorine are weaker than in F due to bigger size}$ $\text{of chlorine.}$$ $\text{4.) Sulphur is a member of chalcogen i.e., ore-producing elements}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}