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Current Question (ID: 10647)

Question:

$\text{The physical property of hydrides of group 16 that decreases down the group is:}$

Options:

1. $\text{Melting point}$
2. $\text{Thermal stability}$ (Correct)
3. $\text{Boiling point}$
4. $\text{Critical temperature}$

Solution:

$\text{HINT: The thermal stability of hydrides of group 16 decreases down the group.}$ $\text{Explanation:}$ $\text{The thermal stability decreases as the atomic mass increases. Water dissociates at 2000°C while tellurium hydride, H}_2\text{Te, decomposes at room temperature. This is due to an increase in M-H bond length.}$ $\text{The boiling point, melting point and critical temperature order are the same. Down the group is increasing because of the size of the central atom increases. But the water is an exceptional case.}$ $\text{Due to strong hydrogen bonding in H}_2\text{O the boiling point, melting point and critical temperature are the highest in the group. The order is as follows:}$ $\text{Order of M.P. or B.P. or critical temperature : H}_2\text{O} > \text{H}_2\text{Te} > \text{H}_2\text{Se} > \text{H}_2\text{S}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}