Import Question JSON

Current Question (ID: 10650)

Question:

$\text{Select the correct option based on statements below:}$

Options:

1. $\text{Both (A) and (R) are true and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are true but (R) is not the correct explanation of (A).}$ (Correct)
3. $\text{(A) is true but (R) is false.}$
4. $\text{Both (A) and (R) are false.}$

Solution:

$\text{HINT: Due to hydrogen bonding, water is liquid at ordinary temperature.}\n\n\text{Explanation:}\n\n\text{STEP 1: H}_2\text{O} \text{ is the only hydride of group 16 elements whereas all other are gases. H}_2\text{O} \text{ is a liquid at room temperature because it is highly associated via intermolecular hydrogen bonding.}\n\n\text{STEP 2: From H}_2\text{O} \text{ to H}_2\text{Te}, \text{ the increase in acidic character can be explained in terms of a decrease in bond enthalpy for the dissociation of the H-E bond.}\n\n\text{A decrease in enthalpy for the dissociation of H-E bond down the group, increases the acidity of the hydride of group 16 elements.}\n\n\text{Hence, both Assertion & Reason are true but the reason is not the correct explanation of the assertion.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}