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Current Question (ID: 10653)

Question:
$\text{Select the correct option based on statements below:}$ $\text{Assertion (A): Both rhombic and monoclinic sulphur exist as } \text{S}_8 \text{ but oxygen exists as } \text{O}_2\text{.}$ $\text{Reason (R): Oxygen forms } p\pi - p\pi \text{ multiple bonds due to its small size and small bond length but } p\pi - p\pi \text{ bonding is not possible in sulphur.}$
Options:
  • 1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$ (Correct)
  • 2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
  • 3. $\text{(A) is True but (R) is False.}$
  • 4. $\text{Both (A) and (R) are False.}$
Solution:
$\text{HINT: Oxygen can form } \pi \text{ bonds due to its small size but sulphur cannot form.}$ $\text{Explanation:}$ $\text{Both rhombic and monoclinic sulphur exist as } \text{S}_8 \text{ but oxygen exists as } \text{O}_2\text{, because oxygen forms } p\pi - p\pi \text{ multiple bonds due to its small size and small bond length.}$ $\text{But } p\pi - p\pi \text{ bonding is not possible in sulphur due to its bigger size as compared to oxygen.}$ $\text{The structures of } \text{S}_8 \text{ and } \text{O}_2 \text{ are as follows: } \text{S}_8 \text{ forms a crown-shaped molecule with single bonds between sulfur atoms, while } \text{O}_2 \text{ forms a diatomic molecule with a double bond (} \sigma \text{ and } \pi \text{ bonds).}$ $\text{Analysis: Assertion (A) is true - sulfur exists as } \text{S}_8 \text{ rings in both allotropic forms while oxygen exists as } \text{O}_2 \text{ molecules. Reason (R) is also true - oxygen can form } p\pi - p\pi \text{ bonds due to its small size, but sulfur cannot due to its larger size. Most importantly, (R) correctly explains why (A) is true - the ability of oxygen to form multiple bonds allows it to exist as } \text{O}_2\text{, while sulfur's inability to form such bonds leads to the formation of } \text{S}_8 \text{ rings.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}