Import Question JSON

Current Question (ID: 10656)

Question:

$\text{Which of the following statements about H}_2\text{SO}_4 \text{ is false:}$

Options:

1. $\text{It can act as an oxidising agent with copper}$
2. $\text{It acts as a dehydrating agent with sugar}$
3. $\text{It acts as an acid in its reaction with BaO}_2$
4. $\text{It acts as a reducing agent in its reaction with Cu}_2\text{O}$ (Correct)

Solution:

$\text{Hint: H}_2\text{SO}_4 \text{ is a powerful oxidising agent}$ $\text{H}_2\text{SO}_4 \text{ cannot act as a reducing agent, because when a substance acts as a reducing agent, it gets oxidised itself and there is an increase in oxidation number. In H}_2\text{SO}_4 \text{ the O.N. of sulphur is +6, which is the maximum and cannot be increased.}$ $\text{It can act as oxidising agent with copper. The reaction is as follows:}$ $\text{Cu} + 2\text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{SO}_2 + 2\text{H}_2\text{O}$ $\text{As sulphuric acid has a great affinity for water, it acts as a powerful dehydrating agent. It acts as a dehydrating agent with sugar.}$ $\text{The reaction is as follows:}$ $\text{C}_6\text{H}_{12}\text{O}_6 + \text{H}_2\text{SO}_4 \rightarrow 6\text{C}$ $\text{It acts as an acid in its reaction with BaO}_2. \text{ The reaction is as follows:}$ $\text{Ba}_2\text{O} + \text{H}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + \text{H}_2\text{O}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}