Import Question JSON

Current Question (ID: 10664)

Question:

$\text{Compound among the following with an S-S bond is:}$

Options:

1. $\text{H}_2\text{S}_2\text{O}_7$
2. $\text{H}_2\text{SO}_5$
3. $\text{H}_2\text{S}_2\text{O}_8$
4. $\text{H}_2\text{S}_2\text{O}_6$ (Correct)

Solution:

$\text{Hint: If sulphur oxidation is less than + 6, the compound contains S-S bond.}$ $\text{a. The oxidation of sulphur in H}_2\text{S}_2\text{O}_6 \text{ is + 5. The oxidation state is less than +6 hence, H}_2\text{S}_2\text{O}_6 \text{ contains S-S bond.}$ $\text{The structure of H}_2\text{S}_2\text{O}_6 \text{ is as follows: HO-S(=O)_2-S(=O)_2-OH showing direct S-S bond.}$ $\text{b. In H}_2\text{S}_2\text{O}_8\text{, the oxidation state of sulphur is +6.}$ $\text{The structure of peroxydisulfuric acid, H}_2\text{S}_2\text{O}_8 \text{ is as follows: HO-S(=O)_2-O-O-S(=O)_2-OH with O-O peroxide linkage.}$ $\text{c. The oxidation of sulphur in H}_2\text{S}_2\text{O}_7\text{(oleum) is +6.}$ $\text{The structure of pyrosulfuric acid or oleum is as follows: HO-S(=O)_2-O-S(=O)_2-OH with S-O-S linkage.}$ $\text{d. The oxidation state of sulphur in H}_2\text{SO}_5 \text{ is +6. The structure of Caro's acid is as follows: HO-S(=O)_2-O-OH with peroxide linkage.}$ $\text{Hence, the correct answer is option fourth.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}